What is the Maximum Energy for a Child on a Pogo Stick?

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SUMMARY

The maximum energy for a child on a pogo stick is determined by the spring constant (k=2.5 x 10^4 N/m) and the mass of the child and pogo stick (25 kg). The total energy of the system is calculated using the formula for spring potential energy and gravitational potential energy. The correct total energy at maximum spring compression is 101J, which aligns with the textbook answer. The maximum kinetic energy occurs when the potential energy is minimized, specifically at the point where the pogo stick is fully decompressed.

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  • Understanding of spring potential energy (U(spring) = 1/2 kx^2)
  • Knowledge of gravitational potential energy (U(gravity) = mgh)
  • Familiarity with the conservation of energy principle
  • Basic calculus concepts for determining maxima and minima
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  • #31
Yay, I found the position by doing what you said lol. I realized that the spring force has distance in it. F(spring)+W=0 --> -kx=mg and x=-9.8x10^-3

However, I was unable to find the velocity of the max KE. Do you just plug x into 1/2kx^2+mgx=K and solve for v? I did that but it doesn't work.. Something is weird here though, the velocity is only .01 m/s greater than x=0.1m
 
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  • #32
What I did to find the velocity of the max KE was:

101J=1/2mv^2+mgx+1/2kx^2

I plugged -.0098m for x and I solved for v I got 2.8591m/s but the answer says 2.85 m/s. I don't know if I did this correctly because I don't think 5 can be rounded down? I never learned about sig figures and I think I've heard something about 5 being rounded down.

Did I solve the velocity of max KE correctly? I considered all of the potential energies because x is not 0...
 
  • #33
Sorry for the delayed response... I forgot to follow up on this thread. :redface:

AznBoi said:
Yay, I found the position by doing what you said lol. I realized that the spring force has distance in it. F(spring)+W=0 --> -kx=mg and x=-9.8x10^-3
Good.

AznBoi said:
What I did to find the velocity of the max KE was:

101J=1/2mv^2+mgx+1/2kx^2

I plugged -.0098m for x and I solved for v I got 2.8591m/s but the answer says 2.85 m/s. I don't know if I did this correctly because I don't think 5 can be rounded down? I never learned about sig figures and I think I've heard something about 5 being rounded down.

Did I solve the velocity of max KE correctly? I considered all of the potential energies because x is not 0...
You solved it correctly. I wouldn't worry about the 3rd sig figure, since the initial data was only given to 2 sig figures anyway.
 

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