What is the meaning of r in the Schwartzschild metric?.(adsbygoogle = window.adsbygoogle || []).push({});

[tex]

ds^2 = \frac{{dr^2 }}{{1 - \frac{{2GM}}{{c^2 r}}}} + r^2 (d\theta ^2 + \sin ^2 \theta d\varphi ^2 ) - c^2 \left( {1 - \frac{{2GM}}{{c^2 r}}} \right)dt^2

[/tex]

If you were to actually measure the radius, your observation would be affected by the factor

[tex]

\frac{1}{{1 - \frac{{2GM}}{{c^2 r}}}}

[/tex]

So where would you get r from if its not the radius you would measure?

I am used to special relativity where you have two different observers that measure different

values but there are no different observers here. It seems like you are supposed to measure

some space to find r, then move a star there and measure it again to see how r is affected.

That hardly seems practical. Assuming there is already a star there, are you supposed to just

measure the circumference and divide by 2 pi to estimate what r would be if the star wasn't there?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# What is the meaning of r (radius) in Schwartzschild Metric?

Loading...

Similar Threads for meaning radius Schwartzschild |
---|

I Local meaning of the equivalence principle |

I Geometric meaning of complex null vector in Newman-Penrose |

I What is the physical meaning of the Lorenz transformation? |

I Coordinate singularity at Schwarzschild radius |

I Meaning of constants of motion in General Relativity |

**Physics Forums | Science Articles, Homework Help, Discussion**