What is the net torque on a pivoted metal plate due to three forces?

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SUMMARY

The net torque on a pivoted square metal plate due to three forces, F1 = 18.0 N, F2 = 17.0 N, and F3 = 14.6 N, must be calculated about the axis through point O at its center. The correct torque equation is Torque = F * r * sin(θ), where θ is the angle between the force and the lever arm. The user attempted to calculate the torque using incorrect radii and angles, leading to incorrect results of 0.839 Nm and 1.19 Nm. The correct approach involves accurately determining the lever arms for each force and ensuring the angles are correctly applied.

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Homework Statement


A square metal plate 0.180m on each side is pivoted about an axis through point O at its center and perpendicular to the plate. Calculate the net torque about this axis due to the three forces shown in the figure if the magnitudes of the forces are F1 = 18.0 N, F2 = 17.0 N, and F3 = 14.6 N. The plate and all forces are in the plane of the page. Take positive torques to be counterclockwise.

http://session.masteringphysics.com/problemAsset/1039975/3/yf_Figure_10_40.jpg


Homework Equations



Torque=Frsin(x)

The Attempt at a Solution



I tried to solve this problem by adding 0.09[-Torque1 + Torque2 + Torque3 sin(45)], giving me an answer of 0.839 which was the not right and then I tried using half the length of the diagonal of the square as the radius which was 0.127, giving me a net torque of 1.19 which was also wrong. How do I do this problem then?
 
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Check the torque 3. F3 is perpendicular to the diagonal through O.
 

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