Calculating net torque on a plate

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Homework Help Overview

The discussion revolves around calculating the net torque on a square plate with forces acting at each corner. The forces include varying magnitudes and directions, with specific attention to the angles involved.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to calculate the net torque using the formula τ=Frsin(Θ) but expresses confusion over the correct application of the forces and angles. Participants question the assumptions made regarding the resolution of the 40 N force and its impact on torque calculation.

Discussion Status

The discussion is ongoing, with participants providing guidance on checking assumptions about force components and clarifying the torque's dependency on the axis of rotation. There is recognition of the need to consider multiple components of forces when calculating torque.

Contextual Notes

Participants note that the problem may require clarification regarding the axis about which the torque is being calculated, as well as the specific components of the forces involved.

tdashrom
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Homework Statement



I'm supposed to be finding the net torque on a square plate. The sides are 1.7 m in length, with a force acting on each corner (30 N top left pointed right, 60 N top right pointed down, 20 N bottom left pointed up, and 40 N bottom right at an angle of 37 degrees). Just for simplicity I have included the picture of the question, and WebAssign has given the answer.

ecnRzIM.png


Homework Equations



τ=Frsin(Θ)

The Attempt at a Solution



I understand how to get part b from the solution in part a. However, I'm completely stuck on how the answer in part a is reached.

The radius in this case should be 1/2 of the side length, so 0.85 m. The 20, 30, and 60 N forces should all have negative torque values because they are turning clockwise, and the 40 N force will be positive. I have tried -.85*(20+30+60)+(40*sin(37)*.85), which does not give the correct answer. If you multiply the three CW forces by sin(45) you get -45.6, which while close is not accepted by the system. I've reworked this 10 times multiple different ways, but still to no avail. Where am I going wrong?
 
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Always double check whether it should be sin or cos.

Btw, the question should make clear it is the torque about the plate's centre that is required. Since there is a net linear force, the torque depends on the axis.
 
You have assumed that the force of 40N @ 37° is resolved into only one component which produces a torque around the center of the plate. Is this what really happens?
 
SteamKing said:
You have assumed that the force of 40N @ 37° is resolved into only one component which produces a torque around the center of the plate. Is this what really happens?
Yes, that's a better response, thankyou.
 
SteamKing said:
You have assumed that the force of 40N @ 37° is resolved into only one component which produces a torque around the center of the plate. Is this what really happens?

haruspex said:
Yes, that's a better response, thankyou.

Got it, thanks!
 

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