Chemistry What is the number of moles of OH- in 0.3 L OF 0.005 M Ba(OH)- ?

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To find the number of moles of OH- in 0.3 L of 0.005 M Ba(OH)-, it's important to recognize that Ba(OH)- is not the same as Ba(OH)2. The correct approach involves understanding that Ba(OH)- would yield one mole of OH- per mole of Ba(OH)-. Therefore, in 0.005 M Ba(OH)-, the concentration of OH- would also be 0.005 M. Multiplying this concentration by the volume of 0.3 L gives 0.0015 moles of OH-.
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Homework Statement



*0.3 L OF 0.005 M Ba(OH)-

What is the number of moles of OH- in 0.3 L OF 0.005 M Ba(OH)- ?2. The attempt at a solution

In 1 mol ba(oh)2--------> 2 mol OH-
so

In 0.005 M ba(oh)2 ----------------> 2 x 0.005 M OH-

I know I am doing something wrong.

please help

thanks in advance.
 
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You are asked about BaOH-, but you are calculating for Ba(OH)2?
 
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