What is the Path of a Cricket Ball During a Bowler's Run Up?

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Homework Help Overview

The discussion revolves around modeling the path of a cricket ball during a bowler's run-up, focusing on the physics involved in the ball's motion and interactions with the ground.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants explore assumptions about the ball's motion, questioning the nature of its velocity upon bouncing and the implications of different types of collisions (elastic vs inelastic).

Discussion Status

Some participants have provided insights into the physics of bouncing and the conservation of momentum, while others express confusion about specific aspects of the ball's velocity during the bounce. Guidance has been offered regarding the nature of the collision and its effects on velocity.

Contextual Notes

There is an emphasis on understanding the physics of bowling rather than simply throwing the ball, and participants are navigating the complexities of modeling the ball's trajectory and interactions with the ground.

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Homework Statement


model the run up a bowler takes before he throws the cricket ball


Homework Equations


model the path of the cricket ball


The Attempt at a Solution


we can make any assumption. if anyone good in physics please helo me model it.
 
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If this is homework you should have a go yourself first.

PS: He doesn't just "throw" the cricket ball (that would be an illegal delivery) he bowls it with a straight arm. I'm not just being picky. This might help you answer the question.
 
i have done some work and equations. but when balls hits the ground i don't understand how to work it out because bounce on ground before it rise again to touch the bat. at that moment i want to know the initial velcity whether it is zero or not? just confused
 
No not zero velocity. If it bounces the [STRIKE]velocity[/STRIKE] speed just after the bounce won't be very different to that just before the bounce. Just the direction changes.

You could model the impact with the ground as an elastic collision or an inelastic collision or perhaps just assume the speed doesn't change. Although obviously the direction does (up rather than down).

http://en.wikipedia.org/wiki/Elastic_collision

"An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies after the encounter is equal to their total kinetic energy before the encounter" (eg none lost to heat, sound etc)

http://en.wikipedia.org/wiki/Inelastic_collision
"Inelastic collisions may not conserve kinetic energy, but they do obey conservation of momentum"
 
thank u that is really helpfull.
 

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