What is the Plane's Bearing from Its Original Position After Changing Course?

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SUMMARY

The discussion focuses on calculating the plane's bearing after changing course. Initially, the plane travels at 56 km/h on a bearing of 65 degrees for 3 hours, covering a distance of 168 km. Afterward, it changes its heading to a bearing of 90 degrees and flies for an additional hour at the same speed. The final bearing from the original position is determined by using vector addition and trigonometry to find the resultant vector's angle.

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Homework Statement



A plane is flying at 56 km/h at a bearing of 65 degrees. After flying for 3 hours the plane heading is changed to a bearing of 90 degrees. After flying for a further 1 hour at 56 km/h what is the plane's bearing from its original position?



No clue how to answer this question...any help would be great..

Thanks,
 
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Sketch the vectors. Use trigonometry to find their horizontal and vertical components. Add the horizontal components. Add the vertical ones.
Make a new vector with the totals. Sketch them. Use trigonometry to find the angle from beginning to end.
 
Thanks for the reply, but physics is totally new to me and I've been online to try to teach myself but I'm having no luck...can you be more specific.
 
56 km/h at a bearing of 65 degrees
Draw a cross and mark north, south, east, and west on the 4 directions.
From north, go 65 degrees toward east. Draw an arrow from the center of the cross at this angle. Mark its length 56 km/h x 3 hours = 168 km.
At the end of this vector, make a new cross and do the same thing for the second vector.
 

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