What is the Plane's Bearing from Its Original Position After Changing Course?

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Homework Help Overview

The problem involves a plane's movement, initially flying at a bearing of 65 degrees for 3 hours, followed by a change to a bearing of 90 degrees for an additional hour. The objective is to determine the plane's bearing from its original position after these changes.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants suggest sketching vectors and using trigonometry to find horizontal and vertical components. There are inquiries about how to approach the problem given the original poster's unfamiliarity with physics concepts.

Discussion Status

Some guidance has been offered regarding vector representation and the use of trigonometry. The original poster expresses difficulty in understanding the suggestions, indicating a need for more specific explanations. Multiple interpretations of the problem setup are being explored.

Contextual Notes

The original poster mentions a lack of prior knowledge in physics, which may impact their ability to engage with the problem-solving process effectively.

nettie2311
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Homework Statement



A plane is flying at 56 km/h at a bearing of 65 degrees. After flying for 3 hours the plane heading is changed to a bearing of 90 degrees. After flying for a further 1 hour at 56 km/h what is the plane's bearing from its original position?



No clue how to answer this question...any help would be great..

Thanks,
 
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Sketch the vectors. Use trigonometry to find their horizontal and vertical components. Add the horizontal components. Add the vertical ones.
Make a new vector with the totals. Sketch them. Use trigonometry to find the angle from beginning to end.
 
Thanks for the reply, but physics is totally new to me and I've been online to try to teach myself but I'm having no luck...can you be more specific.
 
56 km/h at a bearing of 65 degrees
Draw a cross and mark north, south, east, and west on the 4 directions.
From north, go 65 degrees toward east. Draw an arrow from the center of the cross at this angle. Mark its length 56 km/h x 3 hours = 168 km.
At the end of this vector, make a new cross and do the same thing for the second vector.
 

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