What is the polar form of the given complex number without using the argument?

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Homework Help Overview

The discussion revolves around expressing a complex number, specifically z = -7i, in polar form without using the argument. Participants are exploring the implications of this constraint and the definitions involved in polar representation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to express the complex number in polar form while grappling with the restriction against using the argument. There are discussions about adding multiples of 2π to the angle and confusion regarding the definition of the argument in this context.

Discussion Status

The conversation is ongoing, with various interpretations being explored. Some participants are questioning the definitions and requirements of polar form, while others are considering different angle representations. There is no clear consensus on the correct approach yet.

Contextual Notes

Participants note the ambiguity in the definition of the argument and its acceptable range, which may be affecting their attempts to meet the problem's requirements. There is also mention of waiting for further clarification from a teacher.

cragar
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Homework Statement


Write the given complex number in polar form first using an argument where theta is not equal
to Arg(z)
z=-7i

The Attempt at a Solution


7isin(\frac{-\pi}{2}+2\pi n)
The weird part about this problem it asks me to not use the argument, The argument is the smallest angle of the complex number, So I added 2 pi to it, but it tells me I am wrong on my web assign, the only other thing I can think of is taking out the generic n and just adding 2 pi to it. [/B]
 
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cragar said:
7isin(\frac{-\pi}{2}+2\pi n)
That's not what I understand by polar form.
 
z=x+iy=rcos(x)+irsin(x), that's not polar form
 
cragar said:
z=x+iy=rcos(x)+irsin(x), that's not polar form
My mistake, I was thinking of the exponential form.
It's not clear to me which specific variants you tried, like 7i sin(-π/2), 7i sin(3π/2).
As far as I can make out, there is not universal agreement whether Arg is defined to be in the range (-π, π] or [0, 2π).
 
I tried 7isin(-pi/2) ,and the one with a generic 2*pi*n, I might have to wait till my teacher gets back to me on e-mail, because I am not sure what my web assign is looking for, I might try 3*pi/2 and then add 2*pi to it, Just wanted to make sure I was interpreting it correctly . thanks for the replies
 

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