What Is the Probability of Correctly Guessing the Colors of Cards?

  • Thread starter Thread starter Alexsandro
  • Start date Start date
  • Tags Tags
    Cards
AI Thread Summary
The probability of correctly guessing the colors of four cards, with two red and two black, can be calculated using binomial probability. The probability of guessing all four cards correctly is 1/6, while the probability of guessing none correctly is also 1/6. For guessing exactly two cards correctly, there are six different combinations, leading to a probability of 2/3. The discussion emphasizes the importance of posting questions in the appropriate forum for better assistance. Understanding the binomial distribution is crucial for solving such probability problems.
Alexsandro
Messages
49
Reaction score
0
Hello, I tried to model and answer this question, but I didn't get success. Could someone help me ?

You are told that of the four cards face down on the table, two are red and two are black. If you guess all four at random, what is the probability that you get 0, 2, 4 right ?
 
Physics news on Phys.org
Please PAY ATTENTION to where you are posting. You want one of the homework subforum, and NOT the Academic and Career Guidance.

Zz.
 
There are two possible colors for a card and they are equally likely. Whatever you guess, what is the probability your guess will be correct for a specific card?

What is the probability that all 4 guesses are correct? What is the probability that all 4 guesses are wrong?

The probability that exactly two of your guesses are correct is harder. If you know about "binomial probability", then this is exactly the same as aking for the probability that, if you flip a coin 4 times, it will come up heads exactly twice. Imagine writing "C" for "correct" if you guess a coin correctly, "N" for "not correct" if you guess incorrectly. The difference between this problem and the first two is that if you were guess correctly all 4 times you would write CCCC and there is only one way of doing that, if you were to guess correctly 0 times, you would write NNNN and there is only one way of doing that, but if you guess correctly exactly twice you might have written CCNN, or NNCC, or CNCN, etc. How many different ways are there of writing two C's and two N's?
 
You have six possibilities as follow

R,R B,B
R,B,B,R
R,B,R,B
B,B,R,R
B,R,B,R
B,R,R,B

B IS BLACK , R IS RED

P( o right)= 1/6

P(2 right)= 2*2/6=2/3

P(4 right)=1/6
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top