What Is the Probability of Drawing an Odd, Black, or Even Card from a Deck?

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Homework Help Overview

The discussion revolves around calculating the probability of drawing a card from a standard deck of 52 cards that is either odd, black, or even. Participants are exploring the implications of the union of these sets in the context of probability.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to calculate the probability using set operations and are questioning whether the events are mutually exclusive. There is discussion about the implications of the union of sets and whether the brackets in the notation affect the outcome.

Discussion Status

The conversation is ongoing, with various interpretations being explored. Some participants suggest that the problem may be trivial if all events are unions, while others are clarifying the notation and its impact on the probability calculation.

Contextual Notes

There is uncertainty regarding the correct interpretation of the probability notation, particularly whether the union operations are correct or if intersections were intended. Participants are also considering the implications of the question's phrasing.

gtfitzpatrick
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Homework Statement



a singlecard is drawn from a pack of 52 . what is the probability P((oddUblack)Ueven)

Homework Equations


The Attempt at a Solution



P(oddUblack) = 26/52 + 26/52 - 13/52 = 39/52

so is the next part mutually exclusive( if you draw and odd in the first part it can't be even?)

so my probability is 39/52 + 26/52 which obviously isn't right...
 
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hi gtfitzpatrick! :smile:
gtfitzpatrick said:
a singlecard is drawn from a pack of 52 . what is the probability P((oddUblack)Ueven)

but P((oddUblack)Ueven) = P(oddUeven) = 100% :confused:
 


but then Uwith black so does that mean 0.5?
 


are the laws distributive can i say p((oUe)Ub)?
 
are you sure you have the question right?

it asks for odd or black or even …

everything is odd or black or even​
 


thanks for help Tim.
The question is definatly P((ODD U BLACK) U EVEN)
I can see the way your thinking but do you think the brackets change it?
 


Is it possible that at least one of your "[itex]\cup[/itex]" is supposed to be "[itex]\cap[/itex]"?
 


no they are both U, do you think its a mistake?
 
[itex]Y\cap p![/itex] :biggrin:
 
  • #10


lol very funny :)
 
  • #11


If they are all [itex]\cup[/itex] then the problem is trivial as tiny-tim has told you. [itex]E\cup U[/itex] includes all cards so "adding" all black cards doesn't change anything.
 
  • #12


cool, thanks chaps
 

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