What Is the Probability of Drawing an Odd, Black, or Even Card from a Deck?

[gtfitzpatrick]

Homework Statement

a singlecard is drawn from a pack of 52 . what is the probability P((oddUblack)Ueven)

Homework Equations

The Attempt at a Solution

P(oddUblack) = 26/52 + 26/52 - 13/52 = 39/52

so is the next part mutually exclusive( if you draw and odd in the first part it can't be even?)

so my probability is 39/52 + 26/52 which obviously isn't right...

 

[tiny-tim]

hi gtfitzpatrick!

a singlecard is drawn from a pack of 52 . what is the probability P((oddUblack)Ueven)

but P((oddUblack)Ueven) = P(oddUeven) = 100%

 

[gtfitzpatrick]

but then Uwith black so does that mean 0.5?

 

[gtfitzpatrick]

are the laws distributive can i say p((oUe)Ub)?

 

[tiny-tim]

are you sure you have the question right?

it asks for odd or black or even …

everything is odd or black or even​

 

[gtfitzpatrick]

thanks for help Tim.
The question is definatly P((ODD U BLACK) U EVEN)
I can see the way your thinking but do you think the brackets change it?

 

[HallsofIvy]

Is it possible that at least one of your "$\cup$" is supposed to be "$\cap$"?

 

[gtfitzpatrick]

no they are both U, do you think its a mistake?

 

[tiny-tim]

$Y\cap p!$

 

[gtfitzpatrick]

lol very funny :)

 

[HallsofIvy]

If they are all $\cup$ then the problem is trivial as tiny-tim has told you. $E\cup U$ includes all cards so "adding" all black cards doesn't change anything.

 

[gtfitzpatrick]

cool, thanks chaps