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What is the Radial Acceleration

  1. Feb 24, 2008 #1
    Consider a planet of radius 5.53 106 m with a rotation period of 24.3 hours. Compute the radial acceleration of a point on the surface of the planet at the equator due to its rotation about its axis.

    What is the Radial Acceleration.

    the formula I have is (4Pi^2R/T^2)
  2. jcsd
  3. Feb 24, 2008 #2
    Sorry, but what is the radius? 5.53106m? I don't understand what you wrote.
  4. Feb 24, 2008 #3


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    I think Sunnie means the radius is 5.53 x 10^6 m.
  5. Feb 24, 2008 #4
    If the equation you have given is the correct one for solving this problem then is it not just a case of plugging your values into the equation.


    Your value for r is [tex]5.53\times10^{6}[/tex]

    Your value for t is 24.3 hours.
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