What is the Radial Acceleration

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Homework Help Overview

The discussion revolves around calculating the radial acceleration of a planet's surface at the equator, given its radius and rotation period. The subject area includes concepts of circular motion and acceleration in physics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for radial acceleration and question the clarity of the radius value provided. There is an attempt to clarify the notation and values used in the formula.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the radius and confirming the formula's correctness. There is no explicit consensus yet, but some guidance on interpreting the values has been provided.

Contextual Notes

There appears to be confusion regarding the notation of the radius, with different interpretations of the value presented. The rotation period is also noted to be in hours, which may require conversion for calculations.

Sunnie
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Consider a planet of radius 5.53 106 m with a rotation period of 24.3 hours. Compute the radial acceleration of a point on the surface of the planet at the equator due to its rotation about its axis.

What is the Radial Acceleration.


the formula I have is (4Pi^2R/T^2)
 
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Sorry, but what is the radius? 5.53106m? I don't understand what you wrote.
 
I think Sunnie means the radius is 5.53 x 10^6 m.
 
Sunnie said:
Consider a planet of radius 5.53 106 m with a rotation period of 24.3 hours. Compute the radial acceleration of a point on the surface of the planet at the equator due to its rotation about its axis.

What is the Radial Acceleration.


the formula I have is (4Pi^2R/T^2)

If the equation you have given is the correct one for solving this problem then is it not just a case of plugging your values into the equation.

[tex]\frac{4\pi^{2r}}{t^2}[/tex]

Your value for r is [tex]5.53\times10^{6}[/tex]

Your value for t is 24.3 hours.
 

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