# What is the Radial Acceleration

1. Feb 24, 2008

### Sunnie

Consider a planet of radius 5.53 106 m with a rotation period of 24.3 hours. Compute the radial acceleration of a point on the surface of the planet at the equator due to its rotation about its axis.

the formula I have is (4Pi^2R/T^2)

2. Feb 24, 2008

### _Mayday_

Sorry, but what is the radius? 5.53106m? I don't understand what you wrote.

3. Feb 24, 2008

### hage567

I think Sunnie means the radius is 5.53 x 10^6 m.

4. Feb 24, 2008

### _Mayday_

If the equation you have given is the correct one for solving this problem then is it not just a case of plugging your values into the equation.

$$\frac{4\pi^{2r}}{t^2}$$

Your value for r is $$5.53\times10^{6}$$

Your value for t is 24.3 hours.