What Is the Radial Schrödinger Equation for Hydrogen with Maximum l Value?

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Homework Help Overview

The discussion revolves around the radial Schrödinger equation for a hydrogen atom, specifically when the angular momentum quantum number \( l \) is at its maximum value. The original poster presents a form of the radial wave function and seeks to derive the corresponding Schrödinger equation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the maximum value of \( l \) in relation to \( n \) and the implications for substituting into the radial Schrödinger equation. There are attempts to simplify the equation using computational tools, and questions arise about the complexity of the resulting expressions.

Discussion Status

Some participants have provided guidance on assumptions related to the maximum value of \( l \) and the use of Bohr's radius in the context of the problem. There is an acknowledgment of the challenges in deriving a simplified form of the equation, with some expressing frustration over the complexity of the calculations involved.

Contextual Notes

Participants note the constraints of performing complex derivations without computational assistance, particularly in an exam setting. The discussion also highlights the importance of correctly applying known constants and relationships in the context of the problem.

tuomas22
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Sorry in advance my english, I tried to translate it to english as good as I can

Homework Statement



When l has its maximum value, the hydrogen atom radial equation has a simple form of

R(r) = Arn-1e-r/na0, where a0 is Bohr's radius.

Write the respective radial schrödinger equation.

Homework Equations



Radial Schrödinger Equation:
-\frac{\hbar^2}{2*\mu*r^2}*\frac{d}{dr}(r^2*\frac{dR(r)}{dr})+\left[-\frac{kZe^2}{r}+\frac{\hbar^2*l(l+1)}{2*\mu*r^2}\right]*R(r) = ER(r)

The Attempt at a Solution



I've attempted substituting the given R(r) to the radial equation, but I can't get anything out of it that makes sense. Too long to write it here with this hard latex thing :S

Should I get some nice reduced form or can I expect some equation monster?
 
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tuomas22 said:
Sorry in advance my english, I tried to translate it to english as good as I can

Your translation is very good!:smile:

When l has its maximum value...

This is the key assumption in the problem statement...What is the maximum value of l for any given value of n (remember, only certain values are allowed)?...Substitute that into your radial Schroedinger equation (along with the given function R(r)).
Radial Schrödinger Equation:
-\frac{\hbar^2}{2*\mu*r^2}*\frac{d}{dr}(r^2*\frac{dR(r)}{dr})+\left[-\frac{kZe^2}{r}+\frac{\hbar^2*l(l+1)}{2*\mu*r^2}\right]*R(r) = ER(r)
 
Thanks for answer!
The maximum value of l is n-1 right?
I tried to substitute it but it doesn't get much prettier :)

I'm doing the math with Maple here, and it freaks me out to even think that I should be able to do it without computer, which is the case actually...That's why I think I'm doing something wrong, maybe I understand the equation wrong or something.

Here's a screenshot of my maple session (left side of the equation)
http://img526.imageshack.us/img526/5863/tryw.jpg

If I count the right side in too, I can reduce the Arn-1e-r/na0 term from both sides but still I'm not so sure about it
 
Last edited by a moderator:
You also have an equation for Bohr's radius a_0 right?...And Z=____ for the Hydrogen atom?

When you substitute these things in, you should get a lot of terms canceling each-other out.
 
aaah the bohr radius equation, didnt even think about it :)
(and Z=1 ofcourse)

the next part of the question was to prove that the given R(r) is the solution to the schrödinger equation with l=0, and I got it right now with that bohr radius tip you gave! :)
- \frac{1}{2} \frac{k^{2}e^{4}\mu}{\hbar ^{2}} = E

But with l=n-1 I still get horrible monster equations...*cry* nothing seems to cancel out

there must be something I'm doing wrong since I can't be expected to do that kind of differentations without computer in a 2 hour exam ! No human could do it right! :D
(this is an old exam question)
 
Last edited:
Aaah I got it!
0 = 0 finally :)
There was some silly mistake in the equation.

The derivation is still inhumane to do with pen and paper though :)

Thanks much gabbagabbahey!
 

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