What Is the Rate Law for the Uncatalyzed Reaction of Cerium and Thallium Ions?

[shawonna23]

Homework Statement

Cerium and thallium ions react as follows:

2Ce4+ (aq) + Tl+ (aq) ---> 2Ce3+ (aq) + Tl3+ (aq)

This reaction is very slow and is thought to occur in a single elementary step. The reaction is catalyzed by the addition of Mn2+(aq) according to the following mechanism:

Ce(4+) + Mn(2+) ------> Ce(3+) + Mn(3+)
Ce(4+) + Mn(3+) ------> Ce(3+) + Mn(4+)
Tl(+) + Mn(4+) ------> Tl(3+) + Mn(2+)

What is the rate law for the uncatalyzed reaction?

Homework Equations

The Attempt at a Solution

Rate=k [Ce4+]^2 [Mn2+]


The rate law of the catalyzed reaction is Rate=k[Ce4+][Mn2+]

 

[shawonna23]

i meant Rate=k [Ce4+]^2 [Tl+] for the uncatalyzed reaction

 

[Borek]

Looks logical.