# What is the ratio of the largest slit width to the smallest?

1. Apr 22, 2007

### Mitchtwitchita

I'm not exactly sure how to get started on this one. Can anybody help me?...Please?

Two different single slits are used in an experiment involving one source of monochromatic light. With slit 1 in place, the first dark fringe is observed at an angle of 45 degrees. With slit 2, the first dark fringe is observed at an angle of 55 degrees.

a) Which slit is widest? Why?

b) What is the ratio of the largest slit width to the smallest?

2. Apr 22, 2007

### cristo

Staff Emeritus
You need to show some work before we can help you. Do you know any equations to do with diffraction through a slit?

3. Apr 22, 2007

### Staff: Mentor

single slit diffraction

You need to understand the diffraction pattern produced by a single slit. Consult your text or try this: Single Slit Diffraction

4. Apr 22, 2007

### Mitchtwitchita

The equation I've tried was sintheta = lamda/w

For a) I plugged in an arbitrary wavelength of 720 nm and found that slit ! was larger and I figure its because the first dark fringe is observed at less of an angle than slit 2. Therefore, the number of pairs of rays that destructively interfere are increased which causes the maxima to decrease.

For b) I used the arbitrary wavelength of 720 nm and plugged it in for both cases (45 degrees and 55 degrees) which resulted in a ratio of 1.17:1

Does this sound plausible to you guys?

5. Apr 22, 2007

### Staff: Mentor

That gives the condition for the first minima. Since you're interested in the width, you can rewrite it as:
$$w = \lambda/\sin \theta$$
Since for angles between 0 and 90 degrees sin(theta) increases with angle, that equation should tell you that a bigger angle implies a narrower slit.

Close enough. But no need to plug in a particular value of wavelength. (Although that's perfectly OK.) Try using the equation to relate a ratio of slit widths to a ratio of sines of the angles.

6. Apr 22, 2007

### Mitchtwitchita

Thanks Doc! You've been a big help and I think I now know what to do. Cheers!