..... and its classical wave equation?(adsbygoogle = window.adsbygoogle || []).push({});

Suppose in our double sit experimental setup with the usual notion of d,D we have a light of known frequency (v) and wavelength (L)- so its y=Asin(kx-wt). It passes through the two hole and move ahead doing the usual interference stuff, so final wave equation will be y =y1 + y2 = 2A*cos(u/2)*sin(kx-wt+u/2) where u is the phase difference. We can convert phase difference 'u' to path difference 'q'. Now we choose the point of interest on screen (s) which essentially depend upon q. So the final y at s is y=2A*cos(a*s)sin(kx-wt+a*s) where a is constant. Now this y implies a set of wave (because different values s corresponds to interference of different wave with different phase difference) and is function of variable s,x,t. Now since I have put screen at some x (=D), therefore the y reduces to function of two variable s,t. Now rewriting y=2A*cos(u/2)sin(u/2 -wt +kD) which is also a wave equation (but with different meaning). Now the screen acts as our x-axis (or to be precise u-axis). Now intensity is proportional to to sq of wave eqn written above which in turns depends upon u. And what we know is intensity is proportional to number of photon, so we postulate that probability of a photon to hit certain u is proportional to intensity = wave eq ^2. Now is the function y I have written above is psi(wave function) of quantum mechanics with u acting as x(in psi). If not, then what is their relation between them. I have other things to ask depending upon your response. Thank you!

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# What is the relation between wave function on a photon

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