What is the resultant force and what is its consequent acceleration?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the resultant force acting on an object and determining its consequent acceleration based on given forces and angles. The subject area includes vector resolution and dynamics, specifically the relationship between force and acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of horizontal and vertical components of forces using trigonometric functions. There is a focus on the correct application of these functions based on the angle's reference point. Questions arise regarding the validity of the original poster's calculations and the implications of measuring angles from different orientations.

Discussion Status

Some participants provide feedback on the original poster's calculations, suggesting that while the final answers may appear correct, there are concerns about the application of vector resolution techniques and the importance of direction in force and acceleration. The discussion is ongoing with multiple interpretations being explored.

Contextual Notes

There is an emphasis on understanding vector resolution rather than relying solely on memorized formulas. Participants also note potential rounding errors in calculations and the necessity of specifying the direction of forces and accelerations.

looi76
Messages
80
Reaction score
0
[SOLVED] What is the resultant force and what is its consequent acceleration?

Homework Statement


http://img48.imageshack.us/img48/4810/assignment503ij5.png
What is the resultant force acting on the object in the figure, and what is its consequent acceleration?

Homework Equations


F = m.a
Vertical component = F\sin\theta
Horizontal component = F\cos\theta

The Attempt at a Solution



http://img153.imageshack.us/img153/4963/assignment50301fq6.png

Horizontal Component = \cos{45} \times 60 = 42.4N
Vertical Component = \sin{45} \times 60 = 42.4N

http://img81.imageshack.us/img81/1580/assignment50302ns9.png

Horizontal Component = \cos{30} \times 60 = 52.0N
Vertical Component = \sin{30} \times 60 = 30N

Total Horizontal Component = 52 - 42 = 10N
Total Vertical Component = 42 - (30 + 5) = 7N

c^2 = a^2 + b^2
x^2 = 7^2 + 10^2
x = \sqrt{7^2 + 10^2}
x = 12.2N

F = m.a

a = \frac{F}{m} = \frac{12.2}{5.0} = 2.4ms^{-2}

Is my answer correct?
 
Last edited by a moderator:
Physics news on Phys.org
looi76 said:
Vertical component = F\sin\theta
Horizontal component = F\cos\theta
You should be careful when applying these formulae, they are not universally valid. To use these formulae the angle must be measured from the horizontal. For example,
looi76 said:
http://img153.imageshack.us/img153/4963/assignment50301fq6.png

Horizontal Component = \cos{45} \times 60 = 42.4N
Vertical Component = \sin{45} \times 60 = 42.4N
This is not correct, since the angle is measured from the vertical.
looi76 said:
http://img81.imageshack.us/img81/1580/assignment50302ns9.png

Horizontal Component = \cos{30} \times 60 = 52.0N
Vertical Component = \sin{30} \times 60 = 30N
However, this solution is correct.

In general, it is better to understand how to resolve vectors rather than remembering specific formulae.
 
Last edited by a moderator:
Thnx Hootenanny, but if I measure it from the horizontal its the same because the angle is 45^o and is the final answer wrong?
 
looi76 said:
Thnx Hootenanny, but if I measure it from the horizontal its the same because the angle is 45^o and is the final answer wrong?

Your final answers look okay to me (but I haven't checked your arithmetic), just be careful of rounding errors since you round off early in your calculations. I just wanted to emphasise that it is better to know how to result vectors rather than remembering formulae.

Secondly, remember than force and acceleration are vectors. Therefore, you need to quote the direction is which they act.
 

Similar threads

Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
1K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
1K
  • · Replies 18 ·
Replies
18
Views
2K
Replies
3
Views
3K
Replies
22
Views
2K
Replies
4
Views
2K