What is the resulting force acting on water tank walls?

AI Thread Summary
The discussion focuses on calculating the force exerted by water pressure on the walls of cylindrical and cuboid tanks. The user presents calculations for both tank types, using a height of 1 meter and a diameter of 1 meter for the cylindrical tank and dimensions of 1m x 1m x 1m for the cuboid tank. The calculated pressure is 9810 Pa, leading to forces of 30 kN for the cylindrical tank and 39.24 kN for the cuboid tank. However, it is noted that the pressure on the sides of the tanks varies with depth, affecting the total force calculation. The user seeks confirmation on the accuracy of their approach and acknowledges the complexity of pressure distribution.
halfaguava
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Hello,

I am trying to calculate the force exerted by the water pressure on the walls of two different water tanks. A cylindrical tank and a cuboid tank.

Are the following calculations correct? (It seems too easy!)

Using generic dimensions:

Cylindrical Tank: Height 1m, Diameter 1m
Cuboid Tank: 1m × 1m ×1m
Tanks are full: P = \rhogh= 1000 × 9.81 × 1 = 9810Pa

Internal Surface Area of Cylindrical Tank: \pi × 1 × 1 = \pim^3
Internal Surface Area of Cuboid Tank: 1 × 1 × 4sides = 4m^3

F = P × A

Force on Walls of Cylindrical Tank: 30kN
Force of Walls of Cuboid Tank: 39.24kN

Thanks in advance!
 
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The problem with that is that the pressure on the sides isn't constant. The pressure on the sides is dependent on how much water is above that point.
 
In that case, I have calculated the total resulting force acting at a third of the way up the wall?
 

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