What is the science behind a diamond's sparkle?

  • Thread starter Thread starter wikidrox
  • Start date Start date
AI Thread Summary
Diamonds appear brilliant due to their high refractive index of approximately 2.42, which causes light to bend significantly as it passes through. This bending, or refraction, separates white light into its constituent colors, creating a spectrum effect known as "fire." The unique cut of diamonds enhances this sparkle by directing light in multiple directions. Additionally, the formula N1/N2 = SIN I / SIN R helps explain the relationship between the refractive indices and the angles of incidence and refraction. Overall, the combination of high refraction and precise cutting contributes to the diamond's captivating brilliance.
wikidrox
Messages
44
Reaction score
0
I was asked by someone, "Why do diamonds appear brilliant to the eye?" I am having trouble coming up with a solid answer. All I could find out was it has a high index of refraction of about 2.42. I need some assistance with this.
 
Physics news on Phys.org
basicaly because of how much light is refracted. The diamond will redirect the light all through out it which gives it the so called fire. A higher index of refraction means more reflected light. I believe the forumla is n is congruent to c over v phase
 
Tom McCurdy said:
basicaly because of how much light is refracted. The diamond will redirect the light all through out it which gives it the so called fire. A higher index of refraction means more reflected light. I believe the forumla is n is congruent to c over v phase

Exactly. The term for it is cleavage.
 
two words: bling bling
 
Well i Certainly Didn't understand what you said but i will explain what i know.

Basicly when light moves through the diamond which does have a refactive index of 2.42 light refracts (bends).

Light is made up off all the diferent colors Red Orange Yellow Green Blue Violet Indigo .

When light moves through an object the light is bent (towards the normal which is perpendicular to the surface its hitting), but, all the different colors bend different amounts, Most of the time it isn't noticable, because the refractive index is low. But in a diamond, where the refractive index is high, the different colors bend enough to break apart the white light into a rainbow of color.

When the light exits the object it is bent again ( away from the normal) and because most cut diamonds have many diferent sides light is bent in many different directions giving it a sparkly effect.

The only forumla you need to know is N1/N2 = SIN I / SIN R
Where N1 = refractive index of first substance and N2 = Refractive index of second substance, I = Incidence and R= Refraction. You can just transpose this forumla around to get what you want.

Of the top of my head I think Red is refracted the most and indigo is refracted the least.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top