What is the Solution to 3x^(-1/2) - 4 = 0?

[Dil1]

solve the equation
3x^(-1/2) - 4 = 0

 

[MarkFL]

I've moved this thread here to our algebra forum since this is a better fit given the question.

We are given to solve:

$$3x^{-\frac{1}{2}}-4=0$$

What do we get if we multiply through by $x^{\frac{1}{2}}\ne0$?

 

[Dil1]

I've moved this thread here to our algebra forum since this is a better fit given the question.

We are given to solve:

$$3x^{-\frac{1}{2}}-4=0$$

What do we get if we multiply through by $x^{\frac{1}{2}}\ne0$?

i don't get it?

 

[MarkFL]

i don't get it?

Well if we multiply through by $x^{\frac{1}{2}}$ we have:

$$3x^{-\frac{1}{2}}x^{\frac{1}{2}}-4x^{\frac{1}{2}}=0x^{\frac{1}{2}}$$

Now, for the first term on the left, we can use the following property of exponents:

$$a^{b}\cdot a^{c}=a^{b+c}$$

So, what does this term become?