DSM_
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If there were no spring then the answer come out to be (6/5)m. Please help.
The discussion revolves around a problem involving a wedge, spring, and block, focusing on the dynamics of the system and the role of gravitational and spring forces. Participants are exploring the implications of the spring's behavior on the overall mechanics of the problem.
There is ongoing exploration of different interpretations of the problem, particularly regarding the assumptions made about the spring's state. Some participants have suggested that energy conservation might lead to a specific answer, while others express uncertainty about the problem's wording and intent.
Participants note the lack of clarity in the problem statement regarding the initial conditions of the spring and the block, which may affect the interpretation of the solution. The discussion reflects a mix of assumptions and interpretations that have not yet reached a consensus.
I agree, and since k does not appear in any of the answers, the questioner agrees the spring is irrelevant.DSM_ said:I thought the spring would just extend and whole thing would act like a string.
If there were no spring then the answer come out to be (6/5)m. Please help.
You are assuming that block M is released with the spring just taut, i.e. at its relaxed length. Yes, that gives answer A, so that is probably what is intended, but I see nothing in the problem statement to justify that assumption.AlephNumbers said:Even when the gravitational force exerted on the block M is equal to the spring force exerted on block M, the block is still moving. Your method presumes that this is not true. If you use conservation of energy to solve for the maximum spring force, answer (A) can be arrived at.
Seems so. Still a poorly worded question, and congratulations to AlephNumbers for guessing what was meant.DSM_ said:Okay, I have to do it with energy conservation.
If block is released when spring is relaxed, if it moves x downwards,
Work done by grav = Potential energy of Spring.
1/2kx^2 = Mgx
kx = 2Mg
Then tension is kx everywhere in string. Then equating to (friction + mgsin37) gives answer (A).
Is this correct?
haruspex said:Seems so. Still a poorly worded question, and congratulations to AlephNumbers for guessing what was meant.