What is the specific heat of the metal in this specific heat problem?

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The discussion focuses on calculating the specific heat of a metal after it is heated and then placed in water, resulting in a temperature change. The initial temperature of the metal is 90 °C, while the water's final temperature is 25 °C, indicating thermal equilibrium. The equation used is based on the principle of conservation of energy, where the heat lost by the metal equals the heat gained by the water. The specific heat of the metal is derived from the equation mcdeltaT = -mcdeltaT, with specific values substituted for mass and temperature changes. Understanding that the final temperature of both substances is the same is crucial for solving the problem accurately.
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Homework Statement



A 12.0 g sample of a metal is heated to 90.0 °C. It is then dropped into 25.0 g of water. The temperature of the water rises from 22.5 to 25.0 °C. The specific heat of water is 4.18 Jg-1°C-1.
Calculate the specific heat of the metal. Express your answer in Jg-1°C-1

Homework Equations

The Attempt at a Solution



Why is the change in temperature for the metal 90 - 25? Why is 25 degrees celsius the initial temp?[/B]
 
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Is that an attempt at solution ?
Who says the initial temp is 25 C ?
 
BvU said:
Is that an attempt at solution ?
Who says the initial temp is 25 C ?
The solution goes like this.qrxn=-qwater
mcdeltat= -mcdeltat
12C(90-25)=-25(25-22.5)(4.184) and solve for C
 
lc99 said:
Why is the change in temperature for the metal 90 - 25? Why is 25 degrees celsius the initial temp?
If the temperature of the water raises up to 25.0 °C and not more, it means that it is the point where there is thermal equilibrium. The metal must be at the same temperature.
 
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