What is the Speed of a Particle After Acceleration?

AI Thread Summary
To determine the speed of a particle after 6.8 seconds of acceleration at 2.7 m/s² to the right and 4.3 m/s² upward, one can use kinematic equations and vector analysis. The particle's acceleration can be treated as two perpendicular components, allowing for the application of the Pythagorean theorem to find the resultant speed. The total speed can be calculated by combining the horizontal and vertical components of acceleration. Additionally, the direction of the particle can be found using trigonometric functions to determine the angle with respect to the horizontal. This approach simplifies the problem into manageable calculations involving basic physics principles.
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Homework Statement


A particle at rest undergoes an acceleration of 2.7 m/s2 to the right and 4.3 m/s2 up.
-What is its speed after 6.8 s?
-What is its direction with respect to the horizontal at this time?
-Answer between −180◦ and +180◦ .
-Answer in units of ◦ .

Homework Equations

The Attempt at a Solution


I don't even know where to start
 
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You could start with what you do know, and find out things you don't.

Do you think "2.7 m/s2 to the right and 4.3 m/s2 up" means the particle is zig-zagging ?
Are you familiar with the Pythaogrean Theorem ?
Do know how to calculate speed, given an acceleration ?
Do you know the simple trigonometry definitions
 
Last edited:
See if there is a kinematic equation to calculate velocity after time given acceleration
If you have both the horizontal and vertical vector components of velocity then see if you can solve for total magnitude of velocity
It might help to think of the two vector components as sides of a right triangle
 
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