shedrick94
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If an atom described by spin-orbit coupling is in a 4P state, why is the spin quantum number s=3/2?
The discussion revolves around the spin quantum number of an atom in a 4P state, focusing on the concepts of spin-orbit coupling, term symbols, and angular momentum in atomic physics. Participants explore the definitions and relationships between quantum numbers in this context.
Participants express varying levels of understanding regarding the terminology and relationships between quantum numbers, indicating that there is no consensus on the clarity of the concepts discussed.
Some participants express uncertainty about the notation and relationships involved in term symbols and angular momentum, suggesting that further clarification may be needed. The discussion does not resolve these uncertainties.
The exponent is 2S+1, so for a quadruplet, 2S+1 = 4 means S=3/2.shedrick94 said:So the angular momentum quantum number is l=1 as it's a P state? How is the value of s determined?
It's a legacy from the earlier days of atomic physics. It follows the same nomenclature as orbitals: s, p, d, f, etc., but with uppercase letters (just as the total orbital angular momentum is L, instead of l for the orbital angular momentum of a single electron).shedrick94 said:Sorry I've never seen this notation before so I wasn't aware of the relationship. So why do we have L=P then?