What is the strength of the earth's electric field

Click For Summary
SUMMARY

The strength of the Earth's electric field at the surface is established at 100 V/m. This measurement indicates the potential difference of 100 volts per vertical meter. The discussion clarifies that electric field strength is not expressed in V/m², but rather in V/m. To determine the average electric charge or energy flow per square meter on the Earth's surface, one must calculate the surface charge density using Gauss's theorem.

PREREQUISITES
  • Understanding of electric fields and their units (V/m).
  • Familiarity with Gauss's theorem in electrostatics.
  • Basic knowledge of electric charge and surface charge density (coulombs/m²).
  • Concept of electric potential difference.
NEXT STEPS
  • Study Gauss's theorem and its applications in electrostatics.
  • Research the relationship between electric fields and surface charge density.
  • Explore the effects of lightning strikes on the Earth's electric field.
  • Investigate the dynamics of electric charge transfer between the Earth and atmosphere.
USEFUL FOR

Students in physics, electrical engineers, and anyone interested in understanding the Earth's electric field and its implications in electrostatics.

Idea04
Messages
194
Reaction score
1

Homework Statement


With the Earth's electric field the strength of the field at the Earth's surface is 100 V/m.
Now I think that means 100 volts per vertical meter height. My question is what is the strength of the Earth's electric field per meter^2 on horizontal Earth's surface?


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
The units of electric field are V/m, not V/m^2. That doesn't make much sense.
 
Sorry, I should probably reword my question. The Earth has an electric charge and is being recharged by lightning strikes through out the world. And I read that the Earth is constantly transfering electric charges into the atmosphere. My question is in one square meter of Earth's surface how much electric charge or energy flows by that point on average.
 
Ok. Then you want the surface charge density (coulombs/m^2). Use Gauss's theorem.
 

Similar threads

Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 41 ·
2
Replies
41
Views
6K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
5K