What is the Temperature at which the Gap Between Two Bars will be Closed?

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SUMMARY

The problem involves determining the temperature at which the gap between a brass bar and an aluminum bar will close. Given the coefficients of linear expansion, 19x10-6 (C°)-1 for brass and 23x10-6 (C°)-1 for aluminum, and their respective lengths of 2.0m and 1.0m, the gap of 1.3x10-3 m at 28°C can be closed at a temperature of 49.3°C. The solution utilizes the linear expansion formula ΔL = αLoΔT, where the total expansion of both bars equals the initial gap.

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  • Basic algebra for solving equations with two variables
  • Familiarity with temperature conversion and calculations
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BOAS
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Homework Statement



A brass bar and an aluminium bar are each attached opposite each other to immovable walls. (There is a diagram, but I think the idea is clear enough). There is a gap between the two bars of 1.3x10-3m at 28°C.

At what temperature will the gap be closed?

coefficient of linear expansion of brass = 19x10-6 (C°)-1
aluminium = 23x10-6 (C°)-1

Length of brass bar = 2.0m
Length of aluminium bar = 1.0m

Homework Equations



ΔL = \alphaLoΔT

The Attempt at a Solution



I'm not sure where to begin really. Obviously part of the problem is that the two rods are not going to meet in the middle as they expand.

I have 2 unknowns for both rods in the equation for linear expansion, so it's not really helpful to rearrange for ΔT and set them equal to each other.

If you could get me started that would be great,

thanks!
 
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What must the sum of the ΔL's equal?
 
1.3 x 10^-3 m

Can I say:

ΔL + ΔL = \alphaLoΔT + \alphaLoΔT

1.3x10^-3 = (3.8x10^-5 + 23x10^-6)ΔT

ΔT = 21.3 degrees C

28 + 21.3 = Temp when bars will touch
 
Last edited:
BOAS said:
1.3 x 10^-3 m

Can I say:

ΔL + ΔL = \alphaLoΔT + \alphaLoΔT

1.3x10^-3 = (3.8x10^-5 + 23x10^-6)ΔT

ΔT = 21.3 degrees C

28 + 21.3 = Temp when bars will touch
I didn't check your arithmetic, but that is definitely the way to solve it.
 
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I'll check and double check.

Thanks a lot!
 

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