What is the the electric field at a point midway between

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SUMMARY

The electric field at a point midway between a -7.39 µC and a +5.17 µC charge, which are 3.32 cm apart, can be calculated using the formula E = kq/r². The calculations yield E1 = 4.1E7 N/C and E2 = -5.97E7 N/C, resulting in a total electric field of 1.014E8 N/C. It is crucial to divide the distance by 2 when calculating the electric field at the midpoint, as the distance from each charge to the midpoint is half of the total separation distance.

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Homework Statement


What is the the electric field at a point midway between a -7.39 uC and a +5.17 uC charge 3.32 cm apart? Take the direction towards the positive charge to be positive.


Homework Equations


E1=kq1/r^2
E2=kq2//r^2
E1+E2=Etotal


The Attempt at a Solution


E1=8.9E9(5.17E-6)/.0332^2
E2=8.9E9(-7.39E-6)/.0332^2
I got 4.1E7 and 5.97E7 which i added up for 1.014E8 N/C
 
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Are you sure you didn't make a sign error for E2?
Also, the charges are 3.32 cm apart. You are situated midway through them. How could then r be 3.32 cm?
 
wow thanks, i didnt even think about how it was in the middle. thanks again so much
 
I'm working on this problem also, and getting something wrong. I'm using the same equation as you. Did you find that dividing r/2 gave you the correct answer?
 
um...ya. so i just divided the r by 2. but u still have to make sure you are squaring it? post up ur numbers and stuff and what you get if you are still having trouble and ill see if i can help you out
 
What is the the electric field at a point midway between a -7.79 uC and a +5.66 uC charge 3.74 cm apart? Take the direction towards the positive charge to be positive.

So I did:

(9E9)(-7.79E-6)/(.00187^2)

and

(9E9)(5.66E-6)/(.00187^2)

then added the two answers together, which isn't working.
 
sorry it took so long, i had a class. it would be .0187 not .00187. that is probably why. does that work now?
 

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