What Is the Total Impulse on a Sliding Block?

AI Thread Summary
The discussion revolves around calculating the total impulse on a 4.0-kg block sliding on a frictionless surface. The block moves at a constant speed of 5.0 m/s until a time-dependent force is applied after two seconds and removed eight seconds later. Participants emphasize the importance of using the equation for impulse, which relates to the area under the force-time graph. The original poster struggles to arrive at the correct impulse value of 42 N and seeks clarification on their calculations. The conversation highlights the need for a clear understanding of impulse and momentum in physics problems.
enchantress95
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Momentum impulse physics question, HELP ASAP please!

Homework Statement


A 4.0-kg block slides along a frictionless surface with a constant speed of 5.0 m/s as shown. Two seconds after it
begins sliding, a horizontal, time-dependent force is applied to the mass. The force is removed eight seconds later. The
graph shows how the force on the block varies with time.
• What is the magnitude of the total impulse of the force acting on the block?
• What, approximately, is the speed of the block at t = 10 seconds?



Homework Equations



p= mv
K.E= 1/2*m*v^2

The Attempt at a Solution


p= mv = 20kg*m/s
K.E= 1/2*m*v^2 = 50 J

I was solving this past paper and the answer is 42N but idk how to get tht :s any help wud be appreciated, thanks!
 
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Welcome to PF;
Please show us your working and how you have been thinking about the problem so far.
That is the best and fastest way to get the help you need.

You are missing an equation - ##p=\int F(t)\; dt##
... which is to say: the change in momentum is the area under the force-time graph.
... what is "specific impulse"?
 
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