What is the true way to determine time parameters from semilog graph?

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SUMMARY

The discussion focuses on determining T2 relaxation times (T2_1 and T2_2) from nuclear magnetic resonance data using bi-exponential fitting. Two methods for fitting the data to a semilog graph are presented: one involves fitting each segment of data points separately, while the other uses extrapolated values from the second segment to refine the first. The consensus emphasizes that there is no definitive method for curve fitting; rather, the quality of the fit and sensitivity to noise are crucial. Tools like Kaleidagraph and Excel are recommended for performing least squares fits.

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Leonid92
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What is the true way to determine time parameters T2 from semilog graph?
Hi all,
I have experimental nuclear magnetic resonance data that describe T2-relaxation of the nuclei in the sample of interest. The experimental points obey bi-exponential dependence: I = I1*exp(-t/T2_1) + I2*exp(-t/T2_2), where I is current intensity, I1 and I2 are intensities which represent fractions of two T2 components - T2_1 and T2_2. The purpose is to calculate T2_1 and T2_2. To calculate T2_1 and T2_2, I fit bi-exponential equation mentioned above to experimental data points. But in order to ensure that calculated T2 values are true, I'd like to build semilog graph. For this, I take natural logarithm of experimental intensities, and thus the vertical axis in the graph is now in ln(I). Then, in obtained semilog graph, I need to divide points into two parts: first part of points will be fitted by linear equation y1 = C1 - t/T2_1, and the second part of points will be fitted by linear equation y2 = C2 - t/T2_2. And here I have two variants of how to do this fitting. The first variant is just to fit each part of data points with linear equation with corresponding initial guesses. And the second variant is the following: first, I fit the second part of points with equation y2 = C2 - t/T2_2, i.e. 7 points as you can see in the attached images. Thus I found C2 and T2_2 from fit. Then, using equation y2 = C2 - t/T2_2, I find ln(I) values for time values corresponding to the first part of points (i.e. first 3 points as you can see in the attached images). After that, I subtract these extrapolated ln(I) values from first three experimental ln(I) values. Let's call these new values as ln(I)1, ln(I)2, ln(I)3. Finally, I fit these 3 points with equation y1 = C1 - t/T2_1 and find the parameters C1 and T2_1. Could you please tell me, which variant of calculating T2 values is true? Please find attached two images which show the difference between two mentioned methods of calculating T2 values.
 

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There is no “true” or “false” way to fit a curve. You just need to check how good the fit is and how sensitive your parameters are to the noise.
 
I don't think this can be done easily using a graph unless T1 and T2 are very different. Otherwise, I would use a least squares fit to the presumed functionality. There are tons of easy-to-use software available to do this, such as Kaleidagraph and Excel.
 
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