What is the velocity needed for a trampoline jump?

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To determine the velocity needed for a trampoline jump at a 53° angle to reach a target 5.2 m away and 6.1 m high, the horizontal (Vx) and vertical (Vy) components of the jump must be calculated. The equations for Vix and Viy involve using trigonometric functions based on the jump angle. Clarification is needed on the correct angle used in calculations, as there is confusion regarding the 30° angle mentioned. Understanding projectile motion principles is essential for solving the problem effectively. The discussion emphasizes the importance of correctly applying physics equations to achieve the desired jump trajectory.
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Homework Statement



A man jumps on a trampoline with an angle of 53\circ with respect to the horizontal. What velocity does he need in order to be caught by the other man who is 5.2 m away from him, and 6.1 m above the ground?

Homework Equations



so I guess...

X= 5.2 m
Y= -6.1 m

am I correct?


The Attempt at a Solution



So far, the only thing I've actually understood is..

Vix = Vxcos30\circ
Viy = Vysin30\circ

Can someone please guide me through this?
 
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What do you know about projectile motion ? Why do you use 30° angle? What is Vx, Vy?

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