What is the velocity of an electron in a benzene molecule?

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    Electron Velocity
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Homework Help Overview

The discussion revolves around calculating the velocity of an electron in a benzene molecule, which is modeled as an electron confined to a hoop. The problem provides specific parameters such as the radius of the benzene molecule and the angular momentum of the electron.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equations relevant to the problem and express uncertainty regarding the variable 'n' in the context of angular momentum. There is a focus on clarifying the notation used in the problem statement.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the notation and the correct interpretation of the angular momentum expression. Some guidance has been offered regarding the equations to consider, but there is no explicit consensus on how to proceed with the calculations.

Contextual Notes

Participants mention a lack of resources, such as textbooks, which may be affecting their understanding of the problem. There is also a reference to confusion caused by the notation in the provided materials.

Anochaa
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Homework Statement


An electron in a benzene molecule makes a reasonable approximation to an electron
confined to a hoop. If the radius of the benzene molecule is about 5x10-10 m, and the
electron has the lowest allowed angular momentum of h/2π, what is the velocity of the
electron? (You may wish to recall the electron mass is 9x10-31 kg, and angular
momentum is L = rp = rmv.)


Homework Equations


I'm not entirely sure.


The Attempt at a Solution


I'm in a really poorly run workshop based class, so we have no textbook and the packets we were given are completely not at all helpful here.
 
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The two equations to use are in the problem.
 
What do you use for n though?
 
Where do you see n?
 
"angular momentum of h/2π"
 
Anochaa said:
What do you use for n though?

Are you sure that is an n? I believe it is a pi.
 
Oooh, my bad. Sorry! That completely threw me off - it looks like an n in the PDF. Now I just feel dumb, haha.
 
It definitely is pi.
 

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