What is the Volume of Air Affected by Heat Released from Cooling Water?

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The discussion focuses on calculating the volume of air affected by the heat released from cooling water. It highlights that the specific heat of water significantly influences air temperature, particularly in coastal areas. The user seeks guidance on how to approach the problem, initially considering equating the energy values of air and water but recognizing the need to incorporate volume. The suggested method involves first determining the mass of the cooling water, then calculating the mass of air that can absorb the released energy, and finally deriving the volume of that air. This approach emphasizes the relationship between the specific heats and densities of water and air in the calculation.
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Homework Statement



The air temperature above the coastal areas
is profoundly influenced by the large specific
heat of water. One reason is that the heat
released when 1 m3 of water cools by 1◦C will
raise the temperature of an enormously larger
volume of air by 1◦C.
Calculate this volume of air. The specific
heat of air is approximately 1 kJ/kg◦ C and
its density is 1.25 kg/m3. The specific heat of water
is 4.19 kJ/kg◦ C and its density is 1000 kg/m3.
Answer in units of m3


Homework Equations



Q=mc\DeltaT

The Attempt at a Solution



I figured you would set the air and water values equal to one another and solve for volume in place of math, but I realize this isn't correct because you have to incorporate volume, help?
 
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How about finding first the mass of the water, then the mass of the air that can absorb the energy from the water, then the volume of that air?
 
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