What is the Work Done by an Ideal Gas Expanding at Constant Temperature?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the work done by an ideal gas expanding at constant temperature, specifically focusing on the scenario where two moles of gas expand to double their initial volume at 400 K.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the work formula and question the logarithmic form used in the calculations. There is an attempt to clarify the difference between logarithm types, specifically between log and natural logarithm (ln).

Discussion Status

Some participants are exploring different logarithmic forms and their implications on the calculations. There is a lack of consensus on the correct approach, as one participant's calculation significantly differs from the expected answer, prompting further inquiry into the methods used.

Contextual Notes

Participants express uncertainty regarding the logarithmic functions and their application in the context of the work done by the gas. There is also a mention of the specific values used in the calculations, including the gas constant and temperature.

vijiraghs
Messages
7
Reaction score
0

Homework Statement



Two moles of an ideal gas expand to double the initial volume at a constant temperature of 400 K. Calculate the work done by the process.

Homework Equations



W=2.303nRTlog(v2/v1)

The Attempt at a Solution



i tried the formula and got 4613.959 J but the answer is 554.6 J
 
Last edited:
Physics news on Phys.org
Are you sure it isn't log(V2/V1)? I'm used to the form W=nRTln(V2/V1). I can't get either of those answers. Can you show how you got that?
 
hage567 said:
Are you sure it isn't log(V2/V1)? I'm used to the form W=nRTln(V2/V1). I can't get either of those answers. Can you show how you got that?

n=2; v2=2*v1;T=400 K; R=8.32

W=2.303nRTlog(v2/v1)
= 2.303*2*8.32*400*log(2v1/v1)
= 2.303*2*8.32*400*log(2)
= 2.303*2*8.32*400*0.3010
= 4613.959

we generally use logarithms and i don't know wat is "ln"
 

Similar threads

  • · Replies 33 ·
2
Replies
33
Views
3K
Replies
16
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 39 ·
2
Replies
39
Views
5K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 12 ·
Replies
12
Views
7K
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
10K