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meee
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ok say i have y^2 = 5x
what does y=?
what does y=?
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I'm not sure what "accept both positive and negative values" means nor what the fact that you write it yourself has to do with it but:Robokapp said:it's [tex]\sqrt{5x}[/tex] of course. The square root undoes the "Squared" but because you write the [tex]\sqrt{ ... }[/tex] yourself you must accept both positive and negative values.
No. The reason that we have to put a +/- sign in front of the square root when solving y2=5 is because we want to define square root to be a function, and a function cannot have more than one output for the same input. Thus, if you take Sqrt(25) you always get 5, never -5.Robokapp said:Edit: However I've seen the raising to a power as somthing including logs or natural logs...and for that you'd need to have positives. I'm assuming that is why it's correct to choose to add a +/- ?
I mean it's probably incorrect due to some deffinitions which I don't know
"Solving for y: y^2=5x" is an algebraic equation in which we are trying to find the value of the variable, y, that makes the equation true.
The first step is to isolate the y variable on one side of the equation by using inverse operations. In this case, we can divide both sides by 5 to get y^2/5 = x.
To solve for y, we need to take the square root of both sides of the equation. This will give us two possible solutions: y = √x or y = -√x.
If the equation is y^2 = -5x, it is not possible to solve for y using real numbers. This is because the square of any real number will always be positive and cannot equal a negative number. Therefore, the solution for y will be imaginary numbers.
Yes, this equation can have two solutions for y: y = √x and y = -√x. This is because when we take the square root of a number, there are two possible solutions - a positive and a negative value.