What is wrong with this flux integral?

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The discussion focuses on a misunderstanding in parameterizing a vector field for a flux integral problem from Stewart's textbook. The main issue identified is the incorrect addition of an extra 'r' in the surface element, which is unnecessary since it is already included in the cross product of the parameterization. A specific example is provided to illustrate the correct approach, emphasizing the need to use the proper area element without duplication. The correct surface element is defined as the cross product of the parameterization derivatives multiplied by the differential parameters. Understanding this concept is crucial for accurately solving the flux integral problem.
james weaver
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I think the issue is how I parameterize my vector field, but not quite sure. In case you were wondering, this is problem # 27, chapter 16.7 of the 8th edition of Stewart. Thanks for any help.

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Your problem is that you add an additional ##r## in your surface element. This is presumably because you think that in polar coordinates you need to use ##r\,dr\,d\theta## for the area element, but the ##r## is already accounted for in the cross product ##\vec r_r \times \vec r_\theta##. (Consider the flux of ##\hat j## through ##y=0## and ##x^2+z^2 \leq 1##, which should clearly be -up to a sign depending on normal direction- ##\int r \, dr\, d\theta## over the same ranges of ##r## and ##\theta## as you have.)

Generally, the surface element as parametrized by ##t## and ##s## is given by
$$
d\vec S = \vec r_t \times \vec r_s \, dt\, ds
$$
 
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