What kind of Integration to use

  • Thread starter Thread starter jdawg
  • Start date Start date
  • Tags Tags
    Integration
Click For Summary
SUMMARY

The discussion centers on the integration of the function ∫(x²)/(e^(x/2)) dx. Participants suggest using integration by parts as a viable method, with a proposed substitution of u = x² and dv = (1/e^(x/2)). A key insight shared is the recommendation to rewrite 1/e^(ax) as e^(-ax) for simplification, particularly when a > 0, which aids in the integration process.

PREREQUISITES
  • Understanding of integration techniques, specifically integration by parts.
  • Familiarity with exponential functions and their properties.
  • Knowledge of substitution methods in calculus.
  • Basic algebraic manipulation skills.
NEXT STEPS
  • Practice integration by parts with various functions.
  • Explore advanced techniques in integration, such as trigonometric substitution.
  • Study the properties of exponential functions in greater depth.
  • Learn about the application of integration in solving differential equations.
USEFUL FOR

Students and educators in calculus, particularly those focusing on integration techniques, as well as anyone looking to enhance their problem-solving skills in mathematical analysis.

jdawg
Messages
366
Reaction score
2

Homework Statement


∫(x2)/(ex/2) dx


Homework Equations





The Attempt at a Solution


I'm not completely sure where to start on this one. I don't see any sort of u substitution working, would integration by parts be a good idea? Maybe let u=x2 and dv=(1/ex/2) ?
 
Physics news on Phys.org
jdawg said:

Homework Statement


∫(x2)/(ex/2) dx


Homework Equations





The Attempt at a Solution


I'm not completely sure where to start on this one. I don't see any sort of u substitution working, would integration by parts be a good idea? Maybe let u=x2 and dv=(1/ex/2) ?

Don't ask: just go ahead and try it for yourself!

BTW: you should always write ##1/e^{ax}## as ##e^{-ax}## whenever ##a > 0##.
 
Ray Vickson said:
Don't ask: just go ahead and try it for yourself!

BTW: you should always write ##1/e^{ax}## as ##e^{-ax}## whenever ##a > 0##.

Haha ok, thanks! It doesn't look as scary now with that e rewritten :)
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
13
Views
3K
Replies
5
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K