What maximal load can be lifted from a depth of 1000 m ?

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Homework Help Overview

The discussion revolves around determining the maximal load that can be lifted from a depth of 1000 meters using a steel rope composed of multiple rods. The problem involves concepts from mechanics and material science, particularly focusing on stress, load calculations, and the effects of depth in different media.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between allowable stress, the number of rods, and the area of each rod to calculate the maximal load. Questions arise regarding the correct application of stress to the total number of rods and the implications of the rope's weight at a significant depth.

Discussion Status

There is ongoing exploration of the calculations involved, with some participants questioning the initial assumptions about the number of rods and the application of stress. The impact of the depth on the calculations is also being discussed, particularly in relation to the medium (air or water) in which the rope operates.

Contextual Notes

Participants note the importance of considering the weight of the rope itself and the density of steel in the calculations. There is uncertainty regarding the medium at the depth of 1000 meters, which affects buoyancy considerations.

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A steel rope consists of 100 rods. The diameter of each rod is 2 mm. The allowable rope stress is 130 N/mm^2.

what maximal load can be lifted from a depth of 1000 m ?

i use 100*130 N/mm^2 = 4*F(max) / pi * (4)

in order to find F(max).Am i correct??how can i use the length given??

thanx
 
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teng125 said:
A steel rope consists of 100 rods. The diameter of each rod is 2 mm. The allowable rope stress is 130 N/mm^2.

what maximal load can be lifted from a depth of 1000 m ?

i use 100*130 N/mm^2 = 4*F(max) / pi * (4)

in order to find F(max).Am i correct??how can i use the length given??
One cannot multiply the stress by the number of rod. The stress in each rod is a maximum of 130 N/mm2.

Each rod can carry a load, so F = Stress * area, then F(rope) = 100 * F(rod). However, the steel rope must lift its weight (mass), so one has to subtract the weight of 1000 m of rope. Density of steel is about 800 kg/m2, and g = 9.81 m/sec2.

Now there is a question about depth - depth in what medium - air or water? The steel would have some bouyancy in water, but not air.
 
think itis in just air.so how can we use the depth in the calculation??
 
"F(rope) = 100 * F(rod). " the 100 is not the number of rods
 
number of rods is not given and have to find
 

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