What Nucleophile Reacts with Tosylated Butanol in Et3N and H3C-CN?

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The reaction of tosylated butanol with triethylamine (Et3N) and H3C-CN involves the initial displacement of chloride from tosyl chloride, followed by the formation of a tosylate. The tosylate then undergoes deprotonation by Et3N, creating an excellent leaving group. The bulky nature of Et3N limits its ability to act as a nucleophile, leading to elimination rather than substitution. Consequently, the reaction results in the formation of but-1-ene. The key takeaway is that the reaction favors elimination due to steric hindrance from the triethylamine.
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Homework Statement


If I react butanol with toluenesulfonyl chloride (you can see that molcule here: http://sbillinghurst.files.wordpress.com/2010/03/440px-p-toluenesulfonyl_chloride_structure-svg.png) and Et3N and use H3C-CN as solvent what do I get?

The Attempt at a Solution


I know the first step is ejecting the Cl from the toluenesulfonyl chloride and then connecting the toluenesulfonyl group to the O from the butanol.
Then I deprotonoted the O with the toluenesulfonyl group with the Et3N using an acid/base reaction. I am then left with an excellent leaving group but I'm not sure what the nucleophile could be; the only good one I find is the Cl- I expulsed from the toluenesulfonyl chloride. Is that right?
 
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In Et3N there is a lone pair on N atom, which can behave as a nucleophile, but due to the three 'Et' groups, it becomes bulky and cannot act as a nucleophile. So, it acts as a base and an elimination reaction takes place, leading to the formation of but-1-ene!
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...

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