What Range of Speeds Can an Object Have Before a String Breaks?

AI Thread Summary
The discussion centers on determining the maximum speed an object can have before a string breaks, given that it can support a stationary load of 25.0 kg. The object in question has a mass of 3.00 kg and rotates on a frictionless table with a radius of 0.800 m. The tension in the string must not exceed the weight of the hanging load, which is 25 kg multiplied by gravity. Participants clarify that the maximum speed can be calculated using the formula v = (F * r / m)^0.5, where F is the maximum tension. Understanding the concept of "hanging load" is crucial for solving the problem correctly.
shawli
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Homework Statement



A light string can support a stationary hanging load of 25.0kg before breaking. An object of mass m = 3.00kg attached to the string rotates on a frictionless, horizontal table in a circle of radius r = 0.800m, and the other end of the string is held fixed. What range of speeds can the object have before the string breaks?

Homework Equations



F = (m*v^2)/r


The Attempt at a Solution



I seem to only be able to solve this question in terms of F. As in, the max velocity can be:

v = (F*0.800/25)^0.5

Yet there is an actual numeric answer to this question.

I'm not sure what to do with the '3.0kg' given. Any hints would be appreciated!
 
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when you spin this 3kg mass, there is a certain amount of tension in the string. The tension in the string cannot exceed 25kg * gravity. So what is the maximum speed you can spin a mass of 3kg so the tension in the string doesn't exceed 25kg * gravity?
 
Ohh, this is the definition of "hanging load"? I understand now! Thank you.
 
shawli said:
Ohh, this is the definition of "hanging load"? I understand now! Thank you.

You're very welcome:smile:
 

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