What speed would a proton need to orbit in an exact circle ?

[mba444]

Homework Statement

Assume the Earth’s magnetic dipole moment
is aligned with the Earth’s rotational axis,
and the Earth’s magnetic field is cylindrically
symmetric (like an ideal bar magnetic).
What speed would a proton need to orbit in
an exact circle around the Earth at a height of
476 km, where the Earth’s magnetic field has
an intensity of 4.81 × 10−8 T? The mass of
a proton is 1.67262 × 10−27 kg and the radius
of Earth is 6.37 × 106 m.
Answer in units of m/s.

Homework Equations

r= m*v/(q*B)

The Attempt at a Solution

i solved for the velocity but it is wrong i think I'm missing a step =S

 

[diazona]

From my perspective you're missing more than a step What did you get and how did you get it?

 

[mba444]

v= (r*q*B)/m
v=(6.3*10^6)(1.6*10^-19)(4.81*10^-8)/(1.67*10^-27)

 

[alphysicist]

v= (r*q*B)/m
v=(6.3*10^6)(1.6*10^-19)(4.81*10^-8)/(1.67*10^-27)

I believe your value for r in this equation is incorrect. The value r is the radius of the particles path; do you see what it needs to be?