What the following statement exactly mean?

  • Thread starter Thread starter lee.spi
  • Start date Start date
  • Tags Tags
    Mean
lee.spi
Messages
21
Reaction score
0
what the following statement exactly mean :"A topological space is a set M with a distinguished collection of subsets,to be called the open sets".and I don't understand the meaning of "distinguished collection ".it's better have some example.thanks
 
Physics news on Phys.org
It means that in order to give a topological space, you need to give two pieces of information:

1) First, you need to give an underlying set ##X##
2) Secondly, you need to give a set ##\mathcal{T}## which consist of subsets of ##X##. This set ##\mathcal{T}## is called the topology. It can be completely arbitrary, but it does need to satisfy the axioms of a topological space.

For example,
1) I give you the set ##X=\mathbb{R}##
2) I give the topology ##\mathcal{T} = \{\emptyset,\mathbb{R}\}##.
These two pieces of data specify a topological space, called an indiscrete space.

Other example:
1) I give you the set ##X=\{0,1\}##
2) I give the topology ##\mathcal{T} = \{\emptyset,\{0,1\},\{0\}\}##
These two pieces of data specify the Sierpinski topological space.

Obviously, not everything will be a topological space. For example
1) I give you ##X=\{0,1,2\}##
2) I give you ##\mathcal{T} = \{\emptyset, \{0,1,2\}, \{0,1\}, \{1,2\}\}##
These are again two pieces of data, but they do not specify a topological space because ##\mathcal{T}## does not satisfy the axioms. Indeed, ##\{0,1\}\cap\{1,2\} = \{1\}## is not in ##\mathcal{T}##.
 
  • Like
Likes 1 person
both “a distinguished collection of subsets”and “to be called the open sets” refer to the set T ?
 
lee.spi said:
both “a distinguished collection of subsets”and “to be called the open sets” refer to the set T ?

Yes, ##\mathcal{T}## is the "distinguished collection of subsets". Any element of ##\mathcal{T}## is by definition an open set.
 
micromass said:
Yes, ##\mathcal{T}## is the "distinguished collection of subsets". Any element of ##\mathcal{T}## is by definition an open set.

now i understand,thanks
 

Similar threads

Replies
12
Views
3K
Replies
5
Views
547
Replies
5
Views
2K
Replies
4
Views
541
Replies
2
Views
2K
Replies
8
Views
2K
Replies
4
Views
2K
Back
Top