What to do when second partial derivative test is inconclusive

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Homework Help Overview

The discussion revolves around the second partial derivative test for a function of two variables, specifically when the test yields inconclusive results at a critical point (0,0). Participants are exploring alternative methods to analyze the nature of the critical point.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of having all second derivatives equal to zero and consider the possibility of using higher-order derivatives or evaluating the function along specific paths to determine the nature of the critical point.

Discussion Status

Some participants have provided suggestions for exploring the behavior of the function along certain lines, such as the axes or the line y=x. There is an acknowledgment of the limitations of the second derivative test and a search for alternative methods, though no consensus or definitive approach has emerged yet.

Contextual Notes

The original poster expresses a need for guidance on how to proceed when the second partial derivative test is inconclusive, indicating a lack of resources or methods in their current understanding.

Zoe-b
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Homework Statement


I have two problems where there is a critical point of f(x,y) at (0,0), but the second derivatives and mixed second derivative are all zero. The second partial derivative test is therefore inconclusive- all the information I can find online/in my notes just says it is inconclusive and doesn't offer an alternative method. If anyone could give me a link or even just tell me what I should be googling that would be really helpful! Thanks.


Homework Equations





The Attempt at a Solution


I vaguely think I could show the critical point was a saddle point if I could show along one curve f(x,y) is positive as (x,y) -> (0,0) and along another curve f(x,y) is negative as (x,y) -> (0,0) but I have no theorem that states this.
 
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so in the single variable case you would consider the 3rd derivative

if you consider a passing along a line eg x or y axis, or y=x, as you say you could either consider the 3rd derivative, however whilst you may be able to show a saddle point, it won't be able to confirm an extremum
 
so what was the function?
 
The first one is f(x,y) = (x^2)y + x(y^2)

but I was really after ideas for a method not the solution.
 
well i don't know any cook book methods, but you could have a think about what happens to the higher order derivatives, or the previous idea

however for this case I would consider the line y=x (or the axes)
 

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