I What triggers a radioactive nucleus to decay spontaneously?

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what conditions must occur randomly to allow a radioactive nucleus to decay spontaneously?
 
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A radioactive decay of a specific kind of atom occurs statistically on average.
We call it half-life,there are not specific conditions which lead to fission of a particular atom.
It is possible to make conditions different, like saturating the material containing the atoms with high energy neutrons,
That's how breeder reactors make Plutonium.
 
There is no "condition" that triggers a nucleus to decay at a specific moment, as far as we know. Each nuclide (type of nucleus) has a certain probability of decaying during the next short time interval: the decay constant ##\lambda## which has units of probabiility per second. It's related to the half-life by ##t_\rm{1/2} = (\ln 2) / \lambda##. The decay constant can be predicted (at least in principle) by applying quantum mechanics or quantum field theory to the system in question.

If ##\lambda = 0.1## per second, then the nucleus has a one-in-ten chance of decaying during the next second. But we can't force it to happen at any particular point in time during that second, and we don't know what (if anything) immediately triggers it.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...

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