What Was the Minimum Initial Kinetic Energy of a 7 kg Shot Put Thrown 18 Meters?

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Homework Help Overview

The discussion revolves around determining the minimum initial kinetic energy of a 7 kg shot put thrown a distance of 18 meters. The problem is situated within the context of projectile motion and energy calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between launch angle and range, specifically questioning whether 45 degrees is the optimal angle for achieving maximum distance. There are attempts to express energy as a function of the launch angle and to identify conditions for minimum energy.

Discussion Status

The discussion is ongoing, with some participants offering guidance on the equations involved and questioning the validity of the range equation presented. Multiple interpretations of the problem are being explored, particularly regarding the optimal launch angle and the equations used.

Contextual Notes

Participants are addressing potential errors in the equations provided, specifically noting concerns about dimensional consistency. There is also a focus on the assumptions related to the launch angle and its impact on energy calculations.

JoeDoe
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Homework Statement



A 7 kg shot put is thrown 18 meters. What was its minimun intial energy?

Homework Equations



When θ = 45°

Range = V0sin(2θ)/g

Velocity = √(R * g)
 
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JoeDoe said:

Homework Statement



A 7 kg shot put is thrown 18 meters. What was its minimun intial energy?

Homework Equations



When θ = 45°

Range = V0sin(2θ)/g

Velocity = √(R * g)
What is the energy of the shot when launched?
Express Energy as a function of θ. When is Energy minimum?

AM
 
JoeDoe said:
Range = V0sin(2θ)/g

Check this equation.

ehild
 
Is 45 degrees the optimal angle?
 
Yes it is, but your equation for the range is wrong. Check the dimension: it is time, not length.

ehild
 

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