What's the "d" in that formula? (work formula)

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The "d" in the formula refers to "differential" or "delta," indicating a change, typically as a function of time. The discussion clarifies that the equation does not assume a constant force; instead, it requires integrating force over a range of displacement. The expression dW = F · dr represents an infinitesimal amount of work done over an infinitesimal displacement, where force is approximately constant during that displacement. As the path progresses, both force and displacement will vary, complicating the interpretation of these differentials. Understanding these nuances is crucial, especially since work often depends on the path taken.
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What's the definition of the "d" in that formula?

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.Scott said:
It a basic calculus term: "differential" or "delta". It indicates a change.
In this case, most likely a change as a function of time.

https://en.wikipedia.org/wiki/Differential_calculus
This equation assumes a constant force?
 
Austin Gibson said:
This equation assumes a constant force?

No it doesn't. This is because to find W, you have to integrate F over the appropriate range of dr.

Zz.
 
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dW=\vec F \cdot d\vec r is an infinitesimal amount work done over the infinitesimal displacement d\vec r,
where \vec F is approximately constant during that displacement.

When this is evaluated over a path, then \vec F and d\vec r will vary as you progress along the path.

It's probably not a good idea to think of these d's as differentials (as in dW is a differential of W
since there is generally no such W because the work done generally depends on the path. In thermodynamics books, this is sometimes written as đW.)
 
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