- #1
asdf1
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for
1. x(x-1)y``+(3x-1)y`+y=0
2. (x^2 -x)y``-xy`+y=0
those are 2 examples of the frobenius method, but i don't understand why those 2 use completely different methods to solve...
1. x(x-1)y``+(3x-1)y`+y=0
2. (x^2 -x)y``-xy`+y=0
those are 2 examples of the frobenius method, but i don't understand why those 2 use completely different methods to solve...