When 2 particle beams meet head on

Masafi
Messages
58
Reaction score
0
When 2 particle beams meet head on, more energy is avaliable than when the particle beam is directed at a fixed target. Why is this?

My textbook gives an explanation which I don't understand, involving rest mass energy. Any alternate explanation or explaining the one given will be great.

Thank you
 
Physics news on Phys.org
To understand it, first look at the low speed case. When two things going at speed x, the relative speed is 2x, so the energy involved is larger than an object hitting a fixed target at speed x.
In particle accelerators, the particles are going close to the speed of light, so the relationship between the particles involves adding energy by adding mass using the Lorentz transformation.
 
Look at Eq 38.3 in
http://pdg.lbl.gov/2009/reviews/rpp2009-rev-kinematics.pdf
This equation converts energy in the center of mass system (colliding beams) to fixed target beams. This equation can be derived from either Eq 38.1 or 38.2.

Bob S
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top