When does the surface charge density equal the electric flux density?

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SUMMARY

The discussion centers on calculating the surface charge density and polarization charge density in a parallel plate capacitor filled with polystyrene, which has a relative permittivity of 2.55. Given an electric field intensity of 10 kV/m and a plate separation of 1.5 mm, the surface charge density can be determined using the equation ρs = D · an. The confusion arises regarding the relationship between surface charge density and the electric field at a conducting surface.

PREREQUISITES
  • Understanding of electric field intensity and its units (kV/m).
  • Familiarity with the concept of relative permittivity (dielectric constant).
  • Knowledge of parallel plate capacitor configurations.
  • Proficiency in using the equation for surface charge density (ρs = D · an).
NEXT STEPS
  • Study the relationship between electric field intensity and surface charge density in capacitors.
  • Learn about the effects of dielectric materials on electric fields and charge distributions.
  • Explore the concept of polarization charge density in dielectric materials.
  • Investigate the implications of conducting surfaces on electric field behavior.
USEFUL FOR

Students and professionals in electrical engineering, particularly those focusing on capacitor design, dielectric materials, and electrostatics.

FOIWATER
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Homework Statement


The electric field intensity in polystyrene (relative permittivity 2.55) filling the space between the plates of a parallel plate capacitor is 10kV/m. The distance between the plates is 1.5mm.
Calculate the surface charge density of free charge on the plates,
and the surface density of polarization charge

Homework Equations


rho s = D dot an

The Attempt at a Solution


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I am having a hard time seeing how the surface charge density equals the d field normal to the surface in this case?
 
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Is it because it's at a conducting surface
 

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