I When is a system coherent or decoherent?

  • I
  • Thread starter Thread starter zekise
  • Start date Start date
  • Tags Tags
    Coherent System
zekise
Messages
53
Reaction score
1
Michael Price said:
...

Hi Michael,

Is it fair to say that whether system A is coherent or decoherent, it is always with respect to another system B? Of course the environment is another system (E), and an observer yet another system (O). So when we specify coherence or decoherence of system A, it is in respect to another system B (or E or O). It is a relational concept. For example A can be coherent w.r.t. B but decoherent w.r.t. system C. A system is not coherent or decoherent by itself.

Now, is it correct to say that if A is fully (100%) decoherent w.r.t. C, then the two systems are entangled?

And if A is fully (100%) coherent w.r.t. B, then A appears as a superposition to B?

Finally, coherence (ǂ) and decoherence (≡) is commutative. A ǂ B ==> B ǂ A, A ≡ B ==> B ≡ A .
Decoherence is transitive, but coherence is not. A ≡ B & B ≡ C ==> A ≡ C .

Coherence (or disentanglement) results in a loss of quantum information between A & B. Thus energy is required.
Decoherence (or entanglement) results is a gain of information between A & B, and energy is released.

Your opinion is appreciated.
Zek
 
Last edited by a moderator:
Physics news on Phys.org
zekise said:
Is it fair to say that whether system A is coherent or decoherent, it is always with respect to another system B? O
[...]
Now, is it correct to say that if A is fully (100%) decoherent w.r.t. C, then the two systems are entangled?

And if A is fully (100%) coherent w.r.t. B, then A appears as a superposition to B?

Finally, coherence (ǂ) and decoherence (≡) is commutative. A ǂ B ==> B ǂ A, A ≡ B ==> B ≡ A .
Decoherence is transitive, but coherence is not. A ≡ B & B ≡ C ==> A ≡ C .

Coherence (or disentanglement) results in a loss of quantum information between A & B. Thus energy is required.
Decoherence (or entanglement) results is a gain of information between A & B, and energy is released.

Your opinion is appreciated.
Zek
I think of decoherence as the release of more than k of entropy, which randomises phases. Entropy requires energy, in the sense that entropy is the release of uncontrolled energy. When that energy is absorbed by another system the two systems will become entangled (their states become correlated), which would seem to be a commutative event. (The two systems become entangled with respect to each other.) Two systems could be entangled together without a third system being involved, but if it were, then they would all be entangled together.

Coherence is simply the state before decoherence, when phase relationships are known. Once coherence is lost it is pretty much lost forever.

Hopefully I have answered all your points?
 
Last edited:
Michael Price said:
... Two systems could be entangled together without a third system being involved, but if it were, then they would all be entangled together.

Coherence is simply the state before decoherence, when phase relationships are known. Once coherence is lost it is pretty much lost forever.
Thanks Michael. I am not sure what you mean by phases or how entropy figures into decoherence.

Is it correct to say that if system A is coherent to system B, then A appears as a superposition to B. And if system A decoheres wrt system B, then an entanglement has been established between the two systems. If so, if TAB is a measure of entanglement between A & B and SAB is a measure of superposition, then TAB.SAB = 1?

Notation: coherence (ǂ) and decoherence (≡). Are the following correct?:

If A ≡ B and A ≡ C then B ≡ C.
If A ≡ B and A ǂ C then B ǂ C.

Since ǂ is commutative, when a photon P is emitted from a laser diode towards a screen (call it environment E), and before it collides with the screen, then P ǂ E. Therefore, it must be the case that E is coherent to P. We can figure the wave function for P, which is typically in respect to the environment E. Can we also figure the wave function for E in respect to P? I hope I am making sense. 😁
 
Not an expert in QM. AFAIK, Schrödinger's equation is quite different from the classical wave equation. The former is an equation for the dynamics of the state of a (quantum?) system, the latter is an equation for the dynamics of a (classical) degree of freedom. As a matter of fact, Schrödinger's equation is first order in time derivatives, while the classical wave equation is second order. But, AFAIK, Schrödinger's equation is a wave equation; only its interpretation makes it non-classical...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
Is it possible, and fruitful, to use certain conceptual and technical tools from effective field theory (coarse-graining/integrating-out, power-counting, matching, RG) to think about the relationship between the fundamental (quantum) and the emergent (classical), both to account for the quasi-autonomy of the classical level and to quantify residual quantum corrections? By “emergent,” I mean the following: after integrating out fast/irrelevant quantum degrees of freedom (high-energy modes...

Similar threads

Back
Top