When will the walking boy reach school?

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The discussion focuses on a problem involving a cyclist and a walking boy, where the cyclist travels at c miles per hour and the walker at w miles per hour. The cyclist reaches school 10 minutes after passing the walker, leading to the conclusion that the distance to school is 10c miles. The time it takes for the walking boy to reach school is calculated as 10c/w minutes, resulting in him arriving 10c/w - 10 minutes after the cyclist. The expression can also be simplified to 10(c-w)/w, highlighting the relative distance and the walker's speed. The calculations emphasize the relationship between their speeds and the time difference in their arrivals at school.
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A boy cycling to school at c miles per hour passes a boy walking there at w miles per hour. 10 minutes later, the cyclist reaches school. How many minutes after that does the other boy reach school?

I know d= 10c.

The difference in their speeds is c - w. I would I find the amount of time after the other boy reaches school?

Thanks
 
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we have distance = 10c
So time taken by the boy who is walking = 10c/w minutes
S0 the person walking will reach school 10c/w-10 minutes after the cyclist .
One interesting thing is the expression can be re wirtten as 10(c-w)/w. 10(c-w) being the relative distance and w being the velocity ...

regards
Mahesh
 
thanks a lot mahesh
 
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